Solving equilibrium problems for the dissociation of a weak acid (or base)
HA <--> H + + A -
|
HA |
H + |
A - |
[initial] |
[HA] o |
0 |
0 |
[change] |
- x |
+ x |
+ x |
[equilibrium] |
[HA] o - x |
x |
x |
solving for x,
The above approximation is reasonable, when the % ionization ≤ 5 %, which occurs at
that is, the above approximation is valid, when K < 0.0025 [HA] o
An alternative condition (% error ≤ 0.05)
Multiply the numerator and denominator by 2, then cross-multiply, and rearrange
.
Square both sides of the inequality and rearrange
.
Square both sides of the inequality, followed by rearrangement and factoring-out [HA]o
K < 0.00953 [HA]o.
___________
above content based on link
also, see link about not needing Q to solve equilibrium problem, where given inital concentration of reactants and products